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Q.

The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ‘a’ is 3 : 2. The value of ‘a’ is (g-Acceleration due to gravity of the earth)

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a

32g

b

g3

c

23g

d

g

answer is B.

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Detailed Solution

mgm(g−a)=32⇒a=g/3
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