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A ray is incident at an angle of incidence i on one surface of a prism of small angle A and emerges normally from the opposite surface. If the refractive index of the material of the prism is μ, the angle of incidence i is nearly equal to

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a

Aμ

b

A2μ

c

μA

d

μA2

answer is C.

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Detailed Solution

Since the ray emerges normally, therefore e=0. According to relation A+δ=i+e, we get i=A+δ Hence by δ=(μ−1)A, we get i=μA,

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