A ray of light enters a rectangular glass slab of refractive index $$3$$ at an angle of incidence $$60$$°. It travels a distance of $$5$$ cm inside the slab and emerges out of the slab. The perpendicular distance between the incident and the emergent rays is

Question

A ray of light enters a rectangular glass slab of refractive index $$3$$ at an angle of incidence $$60$$°. It travels a distance of $$5$$ cm inside the slab and emerges out of the slab. The perpendicular distance between the incident and the emergent rays is

Infinity Learn · Accepted Answer

$$sin$$ $$60$$°$$sin$$ $$r1=3$$ or        $$sin$$ $$r1=$$$$sin$$ $$60$$°$$3$$ or        $$sin$$ $$r1$$ $$=32$$×$$13=12$$ Now, $$sin$$ (i1-r1) $$=d5$$ or         d $$=$$ $$5$$ $$sin$$ (i1-rr) or         d $$=$$ $$5$$ $$sin$$ (60$$°$$-30$$°$$) $$=$$ $$5$$ $$sin$$ $$30$$° $$=$$ $$52cm$$

A ray of light enters a rectangular glass slab of refractive index $\sqrt{3}$ at an angle of incidence 60°. It travels a distance of 5 cm inside the slab and emerges out of the slab. The perpendicular distance between the incident and the emergent rays is

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A ray of light enters a rectangular glass slab of refractive index 3 at an angle of incidence 60°. It travels a distance of 5 cm inside the slab and emerges out of the slab. The perpendicular distance between the incident and the emergent rays is

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A ray of light enters a rectangular glass slab of refractive index $\sqrt{3}$ at an angle of incidence 60°. It travels a distance of 5 cm inside the slab and emerges out of the slab. The perpendicular distance between the incident and the emergent rays is