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A ray of light enters a rectangular glass slab of refractive index 3  at an angle of incidence 600 . It travels a distance of 5cm inside the slab and emerges out of the slab. The perpendicular distance between the incident and the emergent rays is

a
53cm
b
52cm
c
53/2cm
d
5 cm

detailed solution

Correct option is B

sin600sinr1=3 Or sinr1=sin6003Or   sinr1=32×13=12Or  r1=300Now,  sini1−r1=d5Or   d=5sini1−r1Or  d=5sin600−300=5sin300=52

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