A ray of light falls on a plane mirror. When the mirror is turned about an axis at right angles to the plane of the mirror by $$20$$° , the angle between incident ray and new reflected ray is $$45$$° . The angle between the incident ray and original reflected ray is (3$$ $$+$$ $$x) or (83$$ $$+$$ $$x) ° . The value of x is

Question

A ray of  light falls on a plane mirror. When the mirror is turned about an axis at  right angles to the plane of the mirror by $$20$$°     , the angle  between incident ray and new reflected ray is $$45$$°     . The angle  between the incident ray and original reflected ray is (3$$ $$+$$ $$x) or (83$$ $$+$$ $$x) °     . The value of x  is

Infinity Learn · Accepted Answer

$$2i$$−$$2$$θ$$=45$$° $$2i=45+402i=85Angle$$ between incident ray and original reflected ray $$=$$ $$85$$°$$2i+40=452i=5$$°Answer $$=$$ $$5$$° or $$85$$°

Plane mirror

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$2 i - 2 θ = 45 °$
$2 i = 45 + 40$
$2 i = 85$
Angle between incident ray and original reflected ray = 85°
$2 i + 40 = 45$
$2 i = 5 °$
Answer = 5° or 85°

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Plane mirror

Remember concepts with our Masterclasses.

2i−2θ=45° 2i=45+402i=85Angle between incident ray and original reflected ray = 85°2i+40=452i=5°Answer = 5° or 85°

Ready to Test Your Skills?

free study material

$2 i - 2 θ = 45 °$
$2 i = 45 + 40$
$2 i = 85$
Angle between incident ray and original reflected ray = 85°
$2 i + 40 = 45$
$2 i = 5 °$
Answer = 5° or 85°