A ray of light from a denser medium strikes a rarer medium. The reflected and refracted rays make an angle of 90o with each other. The angles of reflection and refraction are r and rI. The critical angle would be

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sin–1 (tan r)

tan–1 (sin r)

sin–1(tan r1)

tan–1(sin r1)

answer is A.

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Detailed Solution

i = r ; r + r1 - 90 ; r1 = 90 - rμrsin r1=μdsin i⇒cosr=1sin θcsin r since μdμr=1sin θc ⇒θc=sin-1tan r

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