A ray of light is incident at an angle i from denser to rare medium. The reflected and the refracted rays are mutually perpendicular. The angle of reflection and the angle of refraction are respectively r and r’, then the critical angle will be
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a
sin−1(sinr)
b
sin−1tanr′
c
sin−1(tani)
d
tan−1(sini)
answer is C.
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Detailed Solution
DμR=sinisinr′⇒RμD=sinr′sini=1sinC ⇒sinC=sinisin(90−r)=sinicosr=sinicosi ( as ∠i=∠r) ⇒sinC=tani⇒C=sin−1(tani)