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Q.

A ray of light is incident at an angle of 600 on one face of a prism which has refracting angle of 300. The ray emerging out of the prism makes an angle of 300 with the incident ray. Find the value of refractive index of the material of the prism .

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answer is 0001.73.

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Detailed Solution

A+δ=i+e 30+30=60+e e=0 ∴r2=0 A=r1+r2 30=r1+0 Apply Snell's law at first surface. (1) ×sini = (μ)×sinr1 ⇒μ = sin 60osin 30o = 3 = 1.73

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