A ray of light is incident at the glass-water interface at an angle i, it emerges finally parallel to the surface of water, then the value of μg would be
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a
(4/3) sin i
b
1/sin i
c
4/3
d
1
answer is B.
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Detailed Solution
For glass−water interface gμw=sin isin r . . . . . iFor water−air interface wμα=sin rsin 90o . . . .ii⇒gμw×wμα=sin isin r×sin rsin 90o=sin i⇒μwμg×μαμw=sin i⇒sin i⇒μg=1sin i