A ray of light incident on the hypotenuse of a right angled prism after travelling parallel to the base inside the prism is incident on second refracting surface. If 'μ ' is the refractive index of material of prism, the maximum value of the base angle for which light is totally reflected from the hypotenuse is
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a
sin-11μ
b
tan-11μ
c
sin-1μ-1μ
d
cos-11μ
answer is D.
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Detailed Solution
If base angle is θ, then angle of incidence on the hypotenuse is i=(900-θ) and for total internal reflection (900-θ)>c ⇒sin(900-θ)>sin c⇒cos θ>1μ⇒θmax= cos-1 1μ