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A ray of light is incident at 50° on the middle of one of the two mirrors arranged at an angle of 60° between them. The ray then touches the second mirror, get reflected back to the first mirror, making an angle of incidence of

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detailed solution

Correct option is C

Let required angle be θFrom geometry of figureIn ∆ABC; α=1800-600+400=800 ⇒β=900-800=100 in ∆ABD; ∠A=600, ∠B=(α+2β) =(80+2×10)=1000and∠D=(90-θ) ∵∠A+∠B+∠D=1800 ⇒600+1000+(900-θ)=1800 ⇒θ=700

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