First slide

Prism

Question

A ray of light is incident normally on one of the face of a prism of angle 30° and refractive index $\sqrt{2}$ . The angle of deviation will be

Moderate

A

26°
B

0°
C

23°
D

15°

Solution

$A = 30^{\circ}, μ = \sqrt{2} . As we know A = r_{1} + r_{2} = 0 + r_{2} \Rightarrow A = r_{2} Applying Snell ’ s law for the surface A C \frac{1}{μ} = \frac{\sin r_{2}}{\sin e} = \frac{\sin A}{\sin e} \Rightarrow \frac{1}{\sqrt{2}} = \frac{\sin 30^{\circ}}{\sin e} \Rightarrow e = 45^{\circ} δ = e - r_{2} = 45^{\circ} - 30^{\circ} = 15^{\circ}$

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