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Q.

A ray of light is incident on a plane mirror, along the direction given by, A→=2i^−3j^+4k^ . Find the unit vector along the reflected ray. Take normal to mirror along the direction of B→=3i^−6j^+2k^

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a

−94i^+237j^+68k^4929

b

−94i^+68j^−237k^4929

c

3i^+6j^−2k^7

d

None of these

answer is A.

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Detailed Solution

Unit vector along reflected ray,eR^ = eI^ - 2 n^.eI^n^=2i^−3j^+4k^29−23i^−6j^+2k^7 . 2i^−3j^+4k^293i^−6j^+2k^7=2i^−3j^+4k^29−26+18+87×29×73i^−6j^+2k^=−94i^+237j^+68k^4929

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