A ray of light is incident on a plane mirror, along the direction given by, A→$$=2i^$$−$$3j^+4k^$$ . Find the unit vector along the reflected ray. Take normal to mirror along the direction of B→$$=3i^$$−$$6j^+2k^$$

Correct option is 1−94i^+237j^+68k^4929

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A ray of light is incident on a plane mirror, along the direction given by, $\vec{A} = 2 \hat{i} - 3 \hat{j} + 4 \hat{k}$ . Find the unit vector along the reflected ray. Take normal to mirror along the direction of $\vec{B} = 3 \hat{i} - 6 \hat{j} + 2 \hat{k}$

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−94i^+237j^+68k^4929

−94i^+68j^−237k^4929

3i^+6j^−2k^7

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detailed solution

Correct option is A

Unit vector along reflected ray,eR^ = eI^ - 2 n^.eI^n^=2i^−3j^+4k^29−23i^−6j^+2k^7 . 2i^−3j^+4k^293i^−6j^+2k^7=2i^−3j^+4k^29−26+18+87×29×73i^−6j^+2k^=−94i^+237j^+68k^4929

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A ray of light is incident on a plane mirror, along the direction given by, A→=2i^−3j^+4k^ . Find the unit vector along the reflected ray. Take normal to mirror along the direction of B→=3i^−6j^+2k^

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Ready to Test Your Skills?

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A ray of light is incident on a plane mirror, along the direction given by, $\vec{A} = 2 \hat{i} - 3 \hat{j} + 4 \hat{k}$ . Find the unit vector along the reflected ray. Take normal to mirror along the direction of $\vec{B} = 3 \hat{i} - 6 \hat{j} + 2 \hat{k}$