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Q.

A ray of light is incident on a plane mirror, along the direction given by vector 2i^−3j^+4k^. Find the unit vector along reflected ray. Take normal to mirror along the direction of vector 3i^−6j^+2k^.

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Detailed Solution

The unit vector along incident ray2i^−3j^+4k^29the unit vector along NormalN^=3i^−6j^+2k^7The unit vector along reflected rayR^=I^−2I^.N^N^solving we getR^=−94i^−237j^+68k^4929

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