A ray of light of intensity I is incident on a parallel glass-slab at a point A as shown in fig. It undergoes partial reflection and refraction. At each reflection 25% of incident energy is reflected. The rays AB and A'B' undergo interference. The ratio Imax/Imin is

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4 : 1

8 : 1

7 : 1

49 : 1

answer is D.

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Detailed Solution

From figure I1=I4 and I2=9I64 ⇒I2I1=916 By using , ImaxImin=I2I1+1I2I1−12=916+1916−12=491

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