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A ray of light refracts from medium 1 into a thin layer of medium 2, crosses the layer and is incident at the critical angle on the interface between the medium 2 and 3 as shown in the figure. If the angle of incidence of ray is θ , the value of θ is :

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a

sin-189

b

sin-11318

c

sin-11316

d

sin-1813

answer is C.

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Detailed Solution

μ2μ1=sin isin r ; 1.61.8=sin θsin r sin r=1618sin θ ; r=c ; 1.31.8=1618sin θ θ=sin-11316

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A ray of light refracts from medium 1 into a thin layer of medium 2, crosses the layer and is incident at the critical angle on the interface between the medium 2 and 3 as shown in the figure. If the angle of incidence of ray is θ , the value of θ is :