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Q.

A ray of light travelling in glass (μg =32) is incident on a glass air surface at the critical angle. If a thin layer of water  ( μw = 4/3) is now poured on the glass air surface, at what angle will the ray of light emerge into air at the water air surface?

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a

600

b

450

c

sin-189

d

900

answer is D.

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Detailed Solution

according to Snell's law μgsin C= μwsin r= μair sin i here sin C =1μg  so μgsinC =1  = μair sin i    μair =1 sin i=1 i=900
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