A ray of light travelling in glass (μg =32) is incident on a glass air surface at the critical angle. If a thin layer of water ( μw = 4/3) is now poured on the glass air surface, at what angle will the ray of light emerge into air at the water air surface?
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a
600
b
450
c
sin-189
d
900
answer is D.
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Detailed Solution
according to Snell's law μgsin C= μwsin r= μair sin i here sin C =1μg so μgsinC =1 = μair sin i μair =1 sin i=1 i=900