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Q.

A ray of light travelling in glass (μ = 3/2) is incident on a horizontal glass-air surface at the critical angle θc If a thin layer of water (μ = 4/3) is now poured on the glass-air surface, the angle at which the ray emerges into air at the water-air surface is

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a

60°

b

45°

c

90°

d

180°

answer is C.

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Detailed Solution

μg sin θc= μ1 sin 90° or                μg sin θc=1 When water is poured,                     μw sin r = μg sin θc or                μw sin r = 1 Again, μa sin θ=μw sin r or         μa sin θ=1 or         Sin θ=1 or θ=90°
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