A ray of light travelling in water is incident on its surface open to air. The angle of incidence is$\theta$ , which is less than the critical angle. Then there will be :

detailed solution

Correct option is C

The ray is incident on the interface of a rarer medium (air) from a denser medium (water), and the angle of incidence is less than the critical angle. The ray will be partly refracted and partly reflected. Also, the Snell’s law n1sinθ1=n2sinθ2 tells that the angle of refraction will be more than then angle of incidence, on entering the air the ray will bend away from the normal.    The angle between the reflected and the refracted ray is less than(1800−2θ) .