A ray of monochromatic light is incident on one refracting face of a prism of angle 75°. It passes through the prism and is incident on the other face at the critical angle. If the refractive index of the material of the prism is 2, the angle of incidence (in degree) on the first face of the prism is
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answer is 45.
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Detailed Solution
From figure A=r1 +c=r1 +sin−11μ ⇒r1=75−sin−11μ ⇒r1=75−45=30∘ From Snell’s law At B μ=sinisinr1⇒2=sinisin30∘⇒i=45∘