The reaction time for an automobile driver is 0.7 sec. If the automobile can be decelerated at 5 m/s2, calculate the total distance travelled in coming to stop from an initial velocity of 8.33 m/s when a signal is observed.

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12.77 m

14.82 m

16.83 m

19.65 m

answer is A.

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Detailed Solution

Distance travelled before brakes are applied = 8.33 x 0.7 = S1and stopping distance =U22a=(8.33)22×5=S2total distance = S1 + S2 = 12.77 m.