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Q.

In a reactor, 2kg of   92U235 fuel is fully used up in 30 days. The energy released per fission is 200 MeV. Given that the Avogadro number, N=6.023×1026 per kilo mole and 1 eV=1.6×10−19J. The power output of the reactor is close to

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a

35MW

b

60MW

c

54MW

d

125MW

answer is B.

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Detailed Solution

Total  energy=massmolar  mass×avogadro  no×200×106×e J​Power=Total  energyTime=2×103×6.023×1023×200×106×1.6×10−19235×30×24×3600W​=63×106W​≃60 MW
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