First slide

Measurement

Question

Read the screw gauge shown below in the figure.
Given that circular scale has 100 divisions and in one complete rotation the screw advances by $1 mm$ .

Moderate

A

10 mm
B

1.65 mm
C

10.65 mm
D

11.65 mm

Solution

L C $= \frac{Pitch}{Number of divisions on circular scale}$
$= \frac{1 mm}{100} = 0.01 mm$
Linear scale reading =10 (pitch) $= 10 mm$
Circular scale reading $= n (LC) = 65 \times 0.01$
$= 0.65 mm$
Total reading $= (10 + 0.65) mm = 10.65 mm$

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