First slide

Ohm's law

Question

The reading of the ammeter as per figure shown is

Moderate

A

$\frac{1}{8} A$
B

$\frac{3}{4} A$
C

$\frac{1}{2} A$
D

2 A

Solution

Resistance across $XY = \frac{2}{3} Ω$
Total resistance $= 2 + \frac{2}{3} = \frac{8}{3} Ω$
Current through ammeter
$= \frac{2}{8 / 3} = \frac{6}{8} = \frac{3}{4} A$

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