The reading of a spring balance corresponds to 100 N while situated at the north pole and a body is kept on it. The weight record on the same scale, if it is shifted to the equator, is (Take, g = 10 ms-2 and radius of the earth, R = 6.4 X 106m) [AIIMS 2015]

At the pole, the weight is same as the actual weight.Thus,    100 N=m10 ms-2⇒m=10 kgAt the equator, the apparent weight is given bymg'=mg-mω2RAlso, the angular speed of an equatorial point on the earth's surface isω=(2π/24×60×60)⇒  ω=7.27×10-5rad/sHence, now,    mg'=100-107.27×10-52×6.4×106                               =  99.66N