First slide
Friction on horizontal surface
Question

The rear side of a truck is open and a box of 40 kg mass is placed 5 m away from the open end as shown in Figure. The coefficient of friction between the box the surface below it is 0.15. On a straight road the truck starts from rest and accelerates with 2 m s-2. At what distance from the starting point does the box fall from the truck? (Ignore the size of the box).
 

Moderate
Solution

ab = aT – µg = 2 – 0.15 × 10 = 2 – 1.5 = 0.5 m/s2
t = \sqrt {\frac{{2S}}{{{a_b}}}} = \sqrt {\frac{{2 \times 5}}{{0.5}}} = \sqrt {\frac{{2 \times 5 \times 10}}{5}}
t = \sqrt {20} \,S
{S^1} = \frac{1}{2}a{t^2} = \frac{1}{2} \times 2 \times 20

S1 = 20m

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