The rear side of a truck is open and a box of mass 20 kg is placed on the truck 4 m away from the open
end ( $μ$ = 015 and g = 10 $m s^{- 2}$ ). The truck starts from rest with an acceleration of 2 $m s^{- 2}$ on a straight
road. The box will fall off the truck when it is at a distance from the starting point equal to

Question

Infinity Learn · Accepted Answer

Maximwn acceleration of the box can be $$/$$!g or $$1.5$$ $$ms-2$$, while acceleration of truck is $$2$$ $$ms-2$$. Therefore, relative acceleration of the box will be ar $$=$$ $$0.5$$ $$ms-2$$ (backward). It will fall off the truck in a time,$$t=2lar=2$$×$$40.5=4$$ s                              ∵$$s=12at2Displacement$$ of truck upto this instant,$$sr=12art2=12$$×$$0.5$$×$$(4)2=4$$ m

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