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In the rectangle, shown below, the two corners have charges q1=5μC and q2=+2.0μC. The work done in moving a charge +3.0 μC from B to A is (take 1/4πε0=1010N-m2/C2)

a
2.8 J
b
3.5 J
c
4.5 J
d
5.5 J

detailed solution

Correct option is A

Work done W=3×10−6(VA−VB); whereVA=1010(−5×10−6)15×10−2+2×10−65×10−2=115×106 voltand VB=1010(2×10−6)15×10−2−5×10−65×10−2=−1315×106 volt∴W=3×10−6115×106−−1315×106=2.8J

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