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Questions  

In the rectangle shown below the two corners have charges q1=5μC  and q2=+2.0μC  The work done in moving a charge +3.0μC From B to A  is (take 1/4πε0=1010   Nm2/C2)

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a
2.8 J
b
2.5 J
c
3.2 J
d
3.5 J

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detailed solution

Correct option is A

Work doneVA=1010−5×10−615×10−2+2×10−65×10−2=115×106 volt                       and  VB=10102×10−615×10−2−5×10−65×10−2=−1315×106 volt ∴WBA= QVA- VB=3×10−6115×106−−1315×106=2.8 J


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