First slide

Work done by Diff type of forces

Question

A rectangular block of dimensions 6m × 4m × 2m and of density 1.5 gm/c.c is lying on horizontal ground with the face of largest area in contact with the ground. The work done in arranging it with its smallest area in contact with the ground is, (g=10m $s^{- 2}$ ) .

Moderate

A

2880 kJ
B

1440 kJ
C

3800 kJ
D

720 kJ

Solution

m = mass of block = (6 x 4 x 2) x 1.5 x $10^{3}$ kg
⇒ m = 72000 kg

.: W = mg.Δh = 72 x $10^{3}$ x 10 x (3-1) J = 1440 KJ.

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