A rectangular block is heated from 0°C to 100°C. The percentage increase in its length is 0.10%. What will be the percentage increase in its volume ?
0.03 %
0.10 %
0.30 %
none of these
Given Δl/l=0⋅10%=0⋅001 and ΔT=100∘CNow Δll=αΔTor 0⋅001=α×100 or α=10−5/∘CFurther γ=3α=3×10−5/∘C∴ ΔVV=γΔT=3×10−5(100)=3×10−3or ΔVV×100=3×10−3(100)=0⋅30%