A rectangular block is heated from 0°C to 100°C. The percentage increase in its length is 0.10%. What will be the percentage increase in its volume ?

Given Δl/l=0⋅10%=0⋅001 and ΔT=100∘CNow     Δll=αΔTor       0⋅001=α×100  or  α=10−5/∘CFurther      γ=3α=3×10−5/∘C∴ ΔVV=γΔT=3×10−5(100)=3×10−3or    ΔVV×100=3×10−3(100)=0⋅30%