A rectangular block of size 10 cm x 8 cm x 5 cm is kept in three different positions P, Q and R in turn as shown in the figure. In each case, the shaded area is rigidly fixed and a definite force F is applied tangentially to the opposite face to deform the block. The displacement of the upper face will be
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a
same in all the three cases
b
maximum in P position
c
maximum in Q position
d
maximum in R position
answer is C.
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Detailed Solution
η=F/Ax/L⇒x=Lη×FAIf η and F are constants, then x∝LAFor maximum displacement, area at which force applied should be minimum and vertical side of the block should be maximum. This condition is satisfied when the block is kept in position (Q).