Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A rectangular coil ABCD carrying a current of 2A is placed in a uniform magnetic field of induction magnetic field of induction B = 2 T in a gravity free space. Length Ab = CD = 4 m and length BC = Ad = 3 m. Then tensions induced in the sides AB and BC are respectively.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

8 N, 16 N

b

12 N, 16 N

c

8 N, 4 N

d

6 N, 8 N

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

TAB = TCD =12i   (BC).B =12×2×3×2  N  = 6 NTBC=12. i(AB).B=12×2×4×2  N = 8 N
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon