A rectangular coil of area $$5.0$$×$$10$$−$$4m2$$ and $$60$$ turns is pivoted about one of its vertical sides. Then coil is in a radial horizontal field of $$90$$ G (radial$$ here means the field lines are in the plane of the coil for any $$rotation). The torsional constant of hair spring connected to the coil if a current of $$2.0$$ mA produces an angular deflection of is $$180$$ is x×$$10$$−$$8Nm/degree$$

Question

A rectangular coil of area  $$5.0$$×$$10$$−$$4m2$$ and $$60$$ turns is pivoted about one of its vertical sides. Then coil is in a radial horizontal field of $$90$$ G (radial$$ here means the field lines are in the plane of the coil for any $$rotation).  The torsional constant of hair spring connected to the coil if a current of $$2.0$$ mA produces an angular deflection of  is  $$180$$ is x×$$10$$−$$8Nm/degree$$

Infinity Learn · Accepted Answer

Torsional constant is given by $$C=INBA$$θ$$C=2.0$$×$$10$$−$$3$$×$$60$$×$$90$$×$$10$$−$$4$$×$$5$$×$$10$$−$$4180$$ $$C=3$$×$$10$$−$$8$$ $$Nm/degree$$ ∴$$x=3.00$$

Applications involving charged particles moving in a magnetic field

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Torsional constant is given by $C = \frac{INBA}{θ}$
$C = \frac{2.0 \times 10^{- 3} \times 60 \times 90 \times 10^{- 4} \times 5 \times 10^{- 4}}{18^{0}} C = 3 \times 10^{- 8} Nm/degree ∴ x = 3.00$

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Applications involving charged particles moving in a magnetic field

Remember concepts with our Masterclasses.

Torsional constant is given by C=INBAθC=2.0×10−3×60×90×10−4×5×10−4180 C=3×10−8 Nm/degree ∴x=3.00

Ready to Test Your Skills?

free study material

Torsional constant is given by $C = \frac{INBA}{θ}$
$C = \frac{2.0 \times 10^{- 3} \times 60 \times 90 \times 10^{- 4} \times 5 \times 10^{- 4}}{18^{0}} C = 3 \times 10^{- 8} Nm/degree ∴ x = 3.00$