The rectangular coil having 100 turns is placed in a uniform magnetic field of 0.05j^ Telsa as shown in figure. The torque acting on the loop is  p×10−3Nmk^ . find p

The magnetic dipole moment of the current carrying coil is given by  M→=NIAn^ =100×0.5×0.08×0.04i^=0.16i^ Am2The torque acting on the coil is τ→=M→×B→=Mi^×j^B =16×10−2×0.05k^ =8×10−3(Nm)k^.