A rectangular coil of length 0.12 m and width 0.1m having 50 turns of wire is suspended vertically in a uniform magnetic field of strength 0.2 Weber/. The coil carries a current of 2 A. If the plane of the coil is inclined at an angle of 30° with the direction of the field, the torque required to keep the coil in stable equilibrium will be
The required torque is
where N is the number of turns in the coil, I is the current through the coil, B is the uniform magnetic field, A is the area of the coil and is the angle between the direction of the magnetic field and normal to the plane of the coil. Here, N = 50, I = 2 A, A = 0.12 m × 0.1 m= 0.012
B = 0.2 Wb / and = 90° - 30° = 60°
=0.20 Nm