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A rectangular coil of 20 turns and area of cross-section 25 cm2 has a resistance of 100 ohm. If a magnetic field which is perpendicular to the plane of the coil changes at the rate of 1000 tesla per second, the current in the coil is

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answer is 3.

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i=|e|R=NR⋅ΔBΔtAcosθ=20100×1000×25×10−4cos0∘⇒i=0.5A

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