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Q.

A rectangular container having length of 0.5 m, breadth of 0.3 m and height of 0.4 m is containing water to a depth of 30 cm. A wooden block of mass 2 kg is gently released on the surface of water and it floats in water. Then hydrostatic pressure on the bottom of the container is

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a

3.133 KNm2

b

4.124 KNm2

c

8.625 KNm2

d

5.15 KNm2

answer is A.

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Detailed Solution

Total force exerted on the bottom of the container is given by F = Weight of water + Weight of block=0.5×0.3×0.3×103×10+2×10 N=470 N∴ Hydrostatic pressure at the bottom of the container =4700.5×0.3Nm2=3.133 KNm2
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