First slide

Surface tension

Question

A rectangular film of liquid is extended from (4 cm x 2 cm) to (5 cm x 4 cm). If the work done is $3 \times 10^{- 4} J$ , the value of the surface tension of the liquid is

Moderate

A

$0.2 {Nm}^{- 1}$
B

$8.0 {Nm}^{- 1}$
C

$0.250 {Nm}^{- 1}$
D

$0.125 {Nm}^{- 1}$

Solution

$W = T (2 ∆ A)$
$\Rightarrow T = \frac{W}{2 ∆ A} = \frac{3 \times 10^{- 4}}{2 \times 12 \times 10^{- 4}} = 0.125 {Nm}^{- 1}$

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