First slide

Motional EMF

Question

A rectangular loop has a sliding connector PQ of length l and resistance R $Ω$ and it is moving with a speed v as shown. The setup is placed in a uniform magnetic field going into the plane of the paper. The three currents I₁ , I₂ and I are :

Moderate

A

$I_{1} = I_{2} = \frac{Blv}{6 R}, I = \frac{Blv}{3 R}$
B

$I_{1} = - I_{2} = \frac{Blv}{R}, I = \frac{2 Blv}{R}$
C

$I_{1} = I_{2} = \frac{Blv}{3 R}, I = \frac{2 Blv}{3 R}$
D

$I_{1} = I_{2} = I = \frac{Blv}{R}$

Solution

Given circuit can be reduced to
$I_{1} + I_{2} = \frac{Blv}{R + \frac{R}{2}} = \frac{2 Blv}{3 R} So, I_{1} = I_{2} = \frac{Blv}{3 R}$

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