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A rectangular loop has a sliding connector PQ of length l and resistance R $Ω$ and it is moving with a speed v as shown. The setup is placed in a uniform magnetic field going into the plane of the paper. The three currents I₁ , I₂ and I are :

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I1=I2=Blv6R, I=Blv3R

I1=-I2=BlvR, I=2BlvR

I1=I2=Blv3R, I=2Blv3R

I1=I2=I=BlvR

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detailed solution

Correct option is C

Given circuit can be reduced toI1+I2=BlvR+R2=2Blv3R So, I1=I2=Blv3R

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A rectangular loop has a sliding connector PQ of length l and resistance R Ω and it is moving with a speed v as shown. The setup is placed in a uniform magnetic field going into the plane of the paper. The three currents I1 , I2 and I are :

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Ready to Test Your Skills?

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A rectangular loop has a sliding connector PQ of length l and resistance R $Ω$ and it is moving with a speed v as shown. The setup is placed in a uniform magnetic field going into the plane of the paper. The three currents I₁ , I₂ and I are :