A rectangular loop of sides $$8$$ cm and $$2$$ cm having resistance of $$1.6$$ Ω is placed in a magnetic field of $$0.3$$ T directed normal to the loop. The magnetic field is gradually reduced at the rate of $$0.02$$ $$T/s$$. How much power is dissipated by the loop as heat ?

Question

A rectangular loop of sides $$8$$ cm and $$2$$ cm having resistance of $$1.6$$ Ω is placed in a magnetic field of $$0.3$$ T directed normal to the loop. The magnetic field is gradually reduced at the rate of $$0.02$$ $$T/s$$. How much power is dissipated by the loop as heat ?

Infinity Learn · Accepted Answer

We know that induced e.m.f. (e) is equal to the product of rate of change of magnetic field and area. $$Hencee=(0$$⋅$$02)$$×$$8$$×$$2$$×$$10$$−$$4=3$$⋅$$2$$×$$10$$−$$5V$$  Now $$i=eR=3$$⋅$$2$$×$$10$$−$$51$$⋅$$6=2$$⋅$$0$$×$$10$$−$$5amp$$ ∴power loss $$=i2R=2$$⋅$$0$$×$$10$$−$$52$$×$$1$$⋅$$6$$ $$=6$$⋅$$4$$×$$10$$−$$10W$$

A rectangular loop of sides 8 cm and 2 cm having resistance of 1.6 $Ω$ is placed in a magnetic field of 0.3 T directed normal to the loop. The magnetic field is gradually reduced at the rate of 0.02 T/s. How much power is dissipated by the loop as heat ?

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A rectangular loop of sides 8 cm and 2 cm having resistance of 1.6 Ω is placed in a magnetic field of 0.3 T directed normal to the loop. The magnetic field is gradually reduced at the rate of 0.02 T/s. How much power is dissipated by the loop as heat ?

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Ready to Test Your Skills?

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A rectangular loop of sides 8 cm and 2 cm having resistance of 1.6 $Ω$ is placed in a magnetic field of 0.3 T directed normal to the loop. The magnetic field is gradually reduced at the rate of 0.02 T/s. How much power is dissipated by the loop as heat ?