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Q.

A rectangular loop of sides 8 cm and 2 cm having resistance of 1.6 Ω is placed in a magnetic field of 0.3 T directed normal to the loop. The magnetic field is gradually reduced at the rate of 0.02 T/s. How much power is dissipated by the loop as heat ?

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a

1.6 x 10-4 W

b

3.2 x 10-8 W

c

6.4 x 10-10 W

d

12.8 x 10-8 W

answer is C.

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Detailed Solution

We know that induced e.m.f. (e) is equal to the product of rate of change of magnetic field and area. Hencee=(0⋅02)×8×2×10−4=3⋅2×10−5V Now i=eR=3⋅2×10−51⋅6=2⋅0×10−5amp ∴power loss =i2R=2⋅0×10−52×1⋅6 =6⋅4×10−10W

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