A rectangular loop with a slide wire of length l is kept in a uniform magnetic field as shown in figure. The resistance of slider is R. neglecting self inductance of the loop find the current in the connector during its motion with a velocity v.
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a
BIV R1+R2+R
b
BIvR1+R2R+R1+R2
c
BIvR1+R2RR1+RR2+R1R2
d
Blv1R1+1R2+1R3
answer is C.
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Detailed Solution
Inductor behaves like a cell of emf ε′=Blv and equivalent ckt isBIV=ε′Hence, i =BIvR+R1R2R1+R2=BIvR1+R2RR1+RR2+R1R2