Questions
A rectangular loop with a sliding conductor of length l is located in a uniform magnetic field perpendicular to the plane of the loop (figure). The magnetic induction is B. The conductor has a resistance R. The sides AB and CD have resistances R1 and R2, respectively. Find the current through the conductor during its motion to the right with a constant velocity v.
detailed solution
Correct option is C
Induced emf = Blv. R is internal resistance of source of emf i.e., of rodTotal resistance of circuit =R+R1R2R1+R2∴ i=BlvR+R1R2R1+R2=BlvR1+R2R1R2+RR1+R2Talk to our academic expert!
Similar Questions
The diagram shows a circuit having a coil of resistance and inductance L connected to a conducting rod PQ which can slide on a perfectly conducting circular ring of radius 10 cm with its centre at 'P'. Assume that friction and gravity are absent and a constant uniform magnetic field of 5 T exists as shown in figure.
At t = 0, the circuit is switched on and simultaneously a time varying external torque is applied on the rod so that it rotates about P with a constant angular velocity 40 rad/s. Find magnitude of this torque (in milli Nm) when current reaches half of its maximum value. Neglect the self-inductance of the loop formed by the circuit.
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