Q.
A rectangular loop with a sliding conductor of length l is located in a uniform magnetic field perpendicular to the plane of the loop (figure). The magnetic induction is B. The conductor has a resistance R. The sides AB and CD have resistances R1 and R2, respectively. Find the current through the conductor during its motion to the right with a constant velocity v.
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a
BlvR1+R2R1R1+R2
b
Bl2vR1+R1R2
c
BlvR1+R2R1R2+RR1+R2
d
Bl2vR1R2+RR1+R2
answer is C.
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Detailed Solution
Induced emf = Blv. R is internal resistance of source of emf i.e., of rodTotal resistance of circuit =R+R1R2R1+R2∴ i=BlvR+R1R2R1+R2=BlvR1+R2R1R2+RR1+R2
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