Questions
A rectangular loop with a sliding connector of Iength 10 cm is situated in a uniform magnetic field perpendicular to plane of loop. The magnetic induction is 0.1 T and resistance of connector (R) is 1 ohm. The sides AB and CD have resistances 2 ohm and 3 ohm respectively. Find the current in the connector during its motion with constant velocity one metre/sec.
detailed solution
Correct option is A
When the connector moves through a distance x, then area covered = I xflux linked = B l x = ϕInduced e.m.f., e=dΦdt=Bldxdt=BlvThis acts as a cell of e.m.f. B I v and internal resistance fl. Effective resistance of the circuit=R1R2R1+R2Total resistance of the circuit=R+R1R2R1+R2∴current i=BlvR+R1R2R1+R2=0⋅1×110×11+(2×3)(2+3)=1220ATalk to our academic expert!
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