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A rectangular loop with a sliding connector of length l = 1.0 m is situated in a uniform magnetic field B = 2T perpendicular to the plane of loop. Resistance of connector is r = 2Ω. Two resistance of 6Ω and 3Ω are connected as shown in figure. The external force required to keep the connector moving with a constant velocity v = 2m/s is

a
6 N
b
4 N
c
2 N
d
1 N

detailed solution

Correct option is C

Motional emf  e=Bvl⇒e=2×2×1=4 VThis acts as a cell of emf E=4 V and internal resistance r=2Ω.This simple circuit can be drawn as follows  Current through the connector i=42+2=1 A∴magnetic force on connector Fm=Bil=2×1×1=2 N         (Towards left)

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Similar Questions

The diagram shows a circuit having a coil of resistance R=2.5Ω and inductance L connected to a conducting rod PQ which can slide on a perfectly conducting circular ring of radius 10 cm with its centre at 'P'. Assume that friction and gravity are absent and a constant uniform magnetic field of 5 T exists as shown in figure.

At t = 0, the circuit is switched on and simultaneously a time varying external torque is applied on the rod so that it rotates about P with a constant angular velocity 40 rad/s. Find magnitude of this torque (in milli Nm) when current reaches half of its maximum value. Neglect the self-inductance of the loop formed by the circuit.


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