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Q.

A rectangular loop with a sliding connector of length l =1.0 m is situated in a uniform magnetic field B = 2T perpendicular to the plane of loop. Resistance of connector is r=2 Ω. Two resistance of 6 Ω and 3 Ω are connected as shown in figure. The external force required to keep the connector moving with a constant velocity v = 2 m/s is

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a

6N

b

4N

c

2N

d

1N

answer is C.

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Detailed Solution

Motional emfε=Bvl ⇒ε=2×2×1=4VThis acts as a cell of emf ε = 4V and internal resistance r = 2Ω.This simple circuit can be drawn as followsCurrent through the connector i=42+2=1A∴Magnetic force on connectorFm=Bil=2×1×1=2N(Towards left)
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A rectangular loop with a sliding connector of length l =1.0 m is situated in a uniform magnetic field B = 2T perpendicular to the plane of loop. Resistance of connector is r=2 Ω. Two resistance of 6 Ω and 3 Ω are connected as shown in figure. The external force required to keep the connector moving with a constant velocity v = 2 m/s is