A rectangular loop with a sliding connector of length l = 1.0 m is situated in a uniform magnetic field B = 2T perpendicular to the plane of loop. Resistance of connector is r = 2Ω. Two resistance of 6Ω and 3Ω are connected as shown in figure. The external force required to keep the connector moving with a constant velocity v = 2m/s is

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6 N

4 N

2 N

1 N

answer is C.

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Detailed Solution

Motional emf e=Bvl⇒e=2×2×1=4 VThis acts as a cell of emf E = 4 V and internal resistance r=2Ω .This simple circuit can be drawn as follows Current through the connector i=42+2=1 A∴magnetic force on connector Fm=Bil=2×1×1=2 N (Towards left) A force of 2N has to be applied towards right.

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