First slide
Radiation
Question

The rectangular surface of  area  8cm × 4cm of a black body at a temperature of 1270C emits energy at rate of E per second. If the length and breadth are reduced to half of its initial value and the temperature is raised to 3270C, the rate of emission of energy will be

Moderate
Solution

l1 = 8cm, b1 = 4cm; l2 = cm, b2 = 2cm
T1 = 1270C = 400k, T2 = 3270C = 600k
\large \frac {E_2}{E_1}=\left ( \frac {T_2}{T_1} \right )^4\left ( \frac {l_2b_2}{l_1b_1} \right )
\large \frac {E_2}{E}=\left ( \frac {600}{400} \right )^4\left ( \frac {4\times 2}{8\times 4} \right )
\large E_2=\frac {81}{64}E
 

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