Q.

The rectangular surface of  area  8cm × 4cm of a black body at a temperature of 1270C emits energy at rate of E per second. If the length and breadth are reduced to half of its initial value and the temperature is raised to 3270C, the rate of emission of energy will be

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

b

c

d

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

l1 = 8cm, b1 = 4cm; l2 = cm, b2 = 2cmT1 = 1270C = 400k, T2 = 3270C = 600k
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon