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The refracting angle of a prism is A, and refractive index of the material of the prism is  cot (A / 2). The angle of minimum deviation is

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a
90° - A
b
180° + 2A
c
180° - 3A
d
180° - 2A

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detailed solution

Correct option is D

As μ=sinA+δ2sinA2cotA2=sinA+δ2sinA2 ∵μ=cotA2cosA2sinA2=sinA+δ2sinA2sinπ2-A2=sinA2+δ2;π2-A2=A2+δ2∴ δ=π-2A=180°-2A


Similar Questions

ABC is an isosceles right angled triangle with the angle BAC 90o. A ray of light parallel to the base BC strikes the face AB.  The refracted ray in the prism strikes the base BC. If the refractive index of the material of the prism is 2, find the total angle of deviation of the final emergent ray


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