The refracting angle of prism is $$14110$$ and refractive index is $$1.5$$. A thin convex lens of focal length $$20$$ cm is placed at distance $$30$$ cm from the point source S as shown in figure. The position of image of point source S is

Question

The refracting angle of prism is $$14110$$ and refractive index is $$1.5$$. A thin convex lens of focal length $$20$$ cm is placed at distance $$30$$ cm from the point source S as shown in figure. The position of image of point source S is

Infinity Learn · Accepted Answer

∵δ$$=($$μ−$$1)A=(1.5$$−$$1)1411$$×π$$180=12$$×$$1411$$×$$227$$×$$180=190$$ ∴$$tan$$δ$$=$$δ$$=h15$$ ⇒$$190=h15$$ ∴$$h=16cm$$ S’ behaves as object for the thin convex lens. For the lens,$$u=$$−$$30cm$$,$$f=+20cm$$∴$$1v$$−$$1u=1f$$ ∵$$1v$$−$$1$$−$$30=120$$ Or $$1v=120$$−$$130=3$$−$$260$$ ∴$$v=60$$ cm ∴h'$$=$$−$$2$$×$$16=$$−$$13cm$$     [∵h'$$h=vu$$]

The refracting angle of prism is ${(\frac{14}{11})}^{0}$ and refractive index is 1.5. A thin convex lens of focal length 20 cm is placed at distance 30 cm from the point source S as shown in figure. The position of image of point source S is

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The refracting angle of prism is 14110 and refractive index is 1.5. A thin convex lens of focal length 20 cm is placed at distance 30 cm from the point source S as shown in figure. The position of image of point source S is

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The refracting angle of prism is ${(\frac{14}{11})}^{0}$ and refractive index is 1.5. A thin convex lens of focal length 20 cm is placed at distance 30 cm from the point source S as shown in figure. The position of image of point source S is